update

Author: Amanullahgit

Hackerrank/Write a Function.py

@@ -1,3 +1,4 @@
+<<<<<<< HEAD
 # We add a Leap Day on February 29, almost every four years. The leap day is an extra, or intercalary day and we add it to the shortest month of the year, February.
 # In the Gregorian calendar three criteria must be taken into account to identify leap years:
 #
@@ -38,4 +39,46 @@ def is_leap(year):
     return leap
 
 year = int(input())
+=======
+# We add a Leap Day on February 29, almost every four years. The leap day is an extra, or intercalary day and we add it to the shortest month of the year, February.
+# In the Gregorian calendar three criteria must be taken into account to identify leap years:
+#
+# The year can be evenly divided by 4, is a leap year, unless:
+# The year can be evenly divided by 100, it is NOT a leap year, unless:
+# The year is also evenly divisible by 400. Then it is a leap year.
+# This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years.Source
+#
+# Task 
+# You are given the year, and you have to write a function to check if the year is leap or not.
+#
+# Note that you have to complete the function and remaining code is given as template.
+#
+# Input Format
+#
+# Read y, the year that needs to be checked.
+#
+# Constraints
+#
+#
+# Output Format
+#
+# Output is taken care of by the template. Your function must return a boolean value (True/False)
+#
+# Sample Input 0
+#
+# 1990
+# Sample Output 0
+#
+# False
+# Explanation 0
+#
+# 1990 is not a multiple of 4 hence it's not a leap year.
+def is_leap(year):
+    leap = False
+    if(year%4==0 and not (year%100==0) or year%400==0):
+        leap = True
+    return leap
+
+year = int(input())
+>>>>>>> 97a7e02 (update)
 print(is_leap(year))

Scripts/renamer.py

@@ -0,0 +1,16 @@
+## script to rename all files in a directory from a list of file names
+
+import os
+
+# list of new filenames
+new_filenames = ['new_file1.txt', 'new_file2.txt', 'new_file3.txt']
+
+# directory containing the files to be renamed
+directory = 'path/to/directory'
+
+# get a list of all files in the directory
+files = os.listdir(directory)
+
+# rename each file
+for i, file in enumerate(files):
+    os.rename(os.path.join(directory, file), os.path.join(directory, new_filenames[i]))