findRestaurant.py

#   -*-   coding: utf-8   -*-
'''
Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings.

You need to help them find out their common interest with the least list index sum. If there is a choice tie between answers, output all of them with no order requirement. You could assume there always exists an answer.

Example 1:
Input:
["Shogun", "Tapioca Express", "Burger King", "KFC"]
["Piatti", "The Grill at Torrey Pines", "Hungry Hunter Steakhouse", "Shogun"]
Output: ["Shogun"]
Explanation: The only restaurant they both like is "Shogun".
Example 2:
Input:
["Shogun", "Tapioca Express", "Burger King", "KFC"]
["KFC", "Shogun", "Burger King"]
Output: ["Shogun"]
Explanation: The restaurant they both like and have the least index sum is "Shogun" with index sum 1 (0+1).
Note:
The length of both lists will be in the range of [1, 1000].
The length of strings in both lists will be in the range of [1, 30].
The index is starting from 0 to the list length minus 1.
No duplicates in both lists.
'''
"""
        :type list1: List[str]
        :type list2: List[str]
        :rtype: List[str]
        """
class Solution(object):
    def findRestaurant(self, list1, list2):
        if len(list1) < len(list2):
            restaurant = {}
            dic = {}
            for i in range(len(list1)):
                dic[list1[i]] = i
            for i in range(len(list2)):
                if list2[i] in dic.keys():
                    restaurant[list2[i]] = i + dic[list2[i]]
        else:
            restaurant = {}
            dic = {}
            for i in range(len(list2)):
                dic[list2[i]] = i
            for i in range(len(list1)):
                if list1[i] in dic.keys():
                    restaurant[list1[i]] = i + dic[list1[i]]
        found = []
        for k,v in restaurant.items():
            if not len(found):
                found.append(k)
                val = v
                continue
            elif v < val:
                found = []
                found.append(k)
                val = v
            elif v == val:
                found.append(k)
            
        return found

if __name__ == "__main__":
	sol = Solution()
	list1 = ["dixyp","uq","q","KFC"]
	list2 = ["yl","fjugc","rlni","dixyp","uq","q","KFC"]
	print(sol.findRestaurant(list1,list2))